For CodeHS 8.3.8, the simplest yet “custom” method is to use a relative to the ASCII code, but explain it as your own invention. The teacher wants to see that you can map characters to unique integers and back. Step 2: Writing the Code – A Bulletproof Solution Here is a complete solution that passes CodeHS’s autograder. It uses a shift of 5 (you can change this to any number).
Happy coding!
| Scheme | Rule | Example ('A') | |--------|------|----------------| | | Add a fixed number to each character’s position | A(0)+3 = 3 | | ASCII-based | Use ord() but modify it (e.g., subtract 30) | 65 → 35 | | Custom Alphabet Map | Create a dictionary: 'A':1, 'B':2,… | 1 | 8.3 8 create your own encoding codehs answers
If you’ve landed here searching for “8.3 8 create your own encoding codehs answers” , you’re likely staring at the CodeHS console, wondering how to transform plain text into a secret cipher. This exercise is a classic in computer science education: it forces you to think like a computer by mapping characters to numbers, then applying a custom rule. For CodeHS 8
Once you submit this, challenge yourself: modify the shift value or try a non-linear transformation. That’s where real computer science begins. It uses a shift of 5 (you can change this to any number)
encoded = encode(secret) print("Encoded list:", encoded)
def encode(message): """ Encodes a string into a list of integers using a custom shift cipher. Each character is converted to its ASCII code, then shifted by +5. """ encoded_list = [] for ch in message: # Custom rule: shift ASCII value by 5 encoded_value = ord(ch) + 5 encoded_list.append(encoded_value) return encoded_list def decode(encoded_list): """ Decodes a list of integers back into the original string. Reverses the shift by subtracting 5 from each integer. """ decoded_message = "" for num in encoded_list: original_char = chr(num - 5) decoded_message += original_char return decoded_message secret = "Hello World" print("Original:", secret)