Transformation Of Graph Dse Exercise May 2026
Whether it’s a quadratic function, trigonometric curve, or an abstract ( y = f(x) ), examiners expect candidates to visualize how algebraic changes alter geometric shapes. This article provides a structured to mastering four core transformations: translation, reflection, scaling, and their composite applications. Part 1: The Four Pillars of Graph Transformation (DSE Core) Before tackling complex exercises, let’s establish the foundational rules. Assume the original graph is ( y = f(x) ).
Stationary points occur when ( g'(x)=0 ). ( g(x) = 2f(1-x) + 1 ) ( g'(x) = 2 \cdot f'(1-x) \cdot (-1) = -2 f'(1-x) ) Set ( g'(x)=0 \implies f'(1-x)=0 ). transformation of graph dse exercise
Now go forth and transform every graph the DSE throws at you! Whether it’s a quadratic function, trigonometric curve, or
| Transformation | Algebraic Change | Effect on Graph | DSE Common Example | |----------------|------------------|----------------|--------------------| | | ( y = f(x - h) ) | Shift RIGHT by ( h ) (if ( h>0 )) | Quadratic vertex shift | | Translation (Vertical) | ( y = f(x) + k ) | Shift UP by ( k ) (if ( k>0 )) | Sine/cosine vertical shift | | Reflection (x-axis) | ( y = -f(x) ) | Flip over x-axis | Exponential decay reflection | | Reflection (y-axis) | ( y = f(-x) ) | Flip over y-axis | Even/odd function tests | | Scaling (Vertical) | ( y = a f(x) ) | Stretch/compress vertically | Amplitude change in trig graphs | | Scaling (Horizontal) | ( y = f(bx) ) | Compress/stretch horizontally | Period change in sin/cos | ⚠️ Common Pitfall in DSE: Horizontal transformations are counter-intuitive . ( y = f(x - 2) ) moves the graph right , not left. ( y = f(2x) ) compresses horizontally (period halves), not expands. Part 2: DSE-Style Exercise Progression We will build from simple recognition to complex composite transformations, mimicking DSE question difficulty. Exercise Set 1: Basic Identification (DSE Paper 2 Warm-up) Question 1: The graph of ( y = x^2 ) is transformed to ( y = (x + 3)^2 - 4 ). Describe the transformation. Assume the original graph is ( y = f(x) )
The graph of ( y = \cos x ) is transformed to ( y = 3\cos(2x - \pi) + 1 ). Describe the sequence.
Start with ( y = x^2 - 4 ) (vertex at (0,-4), roots at ±2). Step 2: Apply modulus: ( y = |x^2 - 4| ) – reflect negative part above x-axis. Step 3: Subtract 1: shift graph down by 1.
The graph of ( y = f(x) ) is translated 3 units right and then reflected in the y-axis to become ( y = \sqrt4 - x^2 ). Find ( f(x) ).